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Mathematics 17 Online
OpenStudy (anonymous):

Log Derivative

OpenStudy (anonymous):

\[f(x) = \ln [ x^ {7} (x + 3)^ {7} (x^2 + 7)^ {3} ]\] f'(x) =

OpenStudy (anonymous):

I'd log your derivative.

OpenStudy (anonymous):

@iPwnBunnies

OpenStudy (anonymous):

if f(x) = ln(u) wouldn't f'(x) = (1/u)(du/dx)?

OpenStudy (anonymous):

someone help me please

OpenStudy (anonymous):

whatcha need mark?

OpenStudy (anonymous):

\[f \left( x \right)=\ln x^7+ \ln \left( x+3 \right)^7+\ln \left( x^2+7 \right)^3\] \[=7 \ln x+7\ln \left( x+3 \right)+3\ln \left( x^2+7 \right)\] \[f \prime \left( x \right)=\frac{ 7 }{ x }+\frac{ 7 }{ x+3 }+\frac{ 6 x }{ x^2+7 }\]

OpenStudy (anonymous):

uhf just more log properties, my book just doesn't explain this very well :( thank you surj

OpenStudy (anonymous):

yw my name is surjit pronounced as surjeet

OpenStudy (anonymous):

Oh thats a nice name, thanks again :)

OpenStudy (anonymous):

@surjithayer why is the 3rd nomial 6/(x^2 + 7) ?

OpenStudy (anonymous):

why is it 6 instead of 3? because of the x squared?

OpenStudy (anonymous):

The answer is 6.

OpenStudy (anonymous):

\[3*\frac{ d }{ dx }\ln \left( x^2+7 \right)=3*\frac{ 1 }{ x^2+7 }\frac{ d }{ dx }\left( x^2+7 \right)=\frac{ 3*2x }{ x^2+7 }\]

OpenStudy (anonymous):

i see.. great :)

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