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OpenStudy (anonymous):
Log Derivative
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OpenStudy (anonymous):
\[f(x) = \ln [ x^ {7} (x + 3)^ {7} (x^2 + 7)^ {3} ]\]
f'(x) =
OpenStudy (anonymous):
I'd log your derivative.
OpenStudy (anonymous):
@iPwnBunnies
OpenStudy (anonymous):
if f(x) = ln(u)
wouldn't f'(x) = (1/u)(du/dx)?
OpenStudy (anonymous):
someone help me please
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OpenStudy (anonymous):
whatcha need mark?
OpenStudy (anonymous):
\[f \left( x \right)=\ln x^7+ \ln \left( x+3 \right)^7+\ln \left( x^2+7 \right)^3\]
\[=7 \ln x+7\ln \left( x+3 \right)+3\ln \left( x^2+7 \right)\]
\[f \prime \left( x \right)=\frac{ 7 }{ x }+\frac{ 7 }{ x+3 }+\frac{ 6 x }{ x^2+7 }\]
OpenStudy (anonymous):
uhf just more log properties, my book just doesn't explain this very well :( thank you surj
OpenStudy (anonymous):
yw my name is surjit pronounced as surjeet
OpenStudy (anonymous):
Oh thats a nice name, thanks again :)
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OpenStudy (anonymous):
@surjithayer why is the 3rd nomial 6/(x^2 + 7) ?
OpenStudy (anonymous):
why is it 6 instead of 3? because of the x squared?
OpenStudy (anonymous):
The answer is 6.
OpenStudy (anonymous):
\[3*\frac{ d }{ dx }\ln \left( x^2+7 \right)=3*\frac{ 1 }{ x^2+7 }\frac{ d }{ dx }\left( x^2+7 \right)=\frac{ 3*2x }{ x^2+7 }\]
OpenStudy (anonymous):
i see.. great :)
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