Question

A density of 1.11 g/cm^3. What is the mass in grams of 387 mL ?

Answer 1

The milliliters is equivalent to a cubic centimeter. So, 387 mL = 387 cm^3

\[\rho = \frac{m}{V}\]
\[m = \rho V\]
\[m = (1.11 \frac{g}{cm^3})(387 cm^3) = 430 grams\]