Question

differentiate ln^2(t+1)

Answer 1

Ln(x) will differentiate into \[\frac{ \frac{ dy }{dx} }{x }\]
In this case our
X=t+1
dy/dx=1

Just put these figures in for your answer.
Hope that helps you out.

Answer 2

the answer is 2ln(t+1)/t+1

i dont understand how to differentiate a squared log

Answer 3

My bad didn't see the ^2

Answer 4

The notation is a little hard to get used to.
It's the same thing we do with trig functions.\[\Large\rm \ln^2(x)=\left[\ln x\right]^2\]The whole thing is being squared.
So your `outermost function` is the square.

Answer 5

Chain rule like you normally would, but deal with the square `before` the log.

Answer 6

I see you have this, hope he helps you out HarryPotter4

Answer 7

thank you guys!! i get it :)

Answer 8

Got it? c: Ok cool.