Two towns, X and Y, are 25 km apart, with Y being due north of X. Town Z is due east of X and 60 km away. Draw a picture and find the distance and bearing of Y from Z??
|dw:1403417147427:dw| \(?=\sqrt{25^2+60^2}\)
Thank-you. How would i then find the bearing of Y from Z?
Pythagorean Theorem, you have 2 sides and a right triangle. That is very important to learn for the future.
I will be sure to remember it. What about the bearing?
@Johnbc
Bearing refers to the angle around the points we are looking at
|dw:1403417909137:dw| For example
Since you have a right angle triangle you can find the angles within the triangle and I believe those are the bearings
Law of sines may be helpful \[\frac{ Sin A }{ a }=\frac{ SinB }{ b }=\frac{ SinC }{ c }\]
I thought it was the other way around. |dw:1403418085937:dw|
same thing
Yes it can be both ways as long as you are consistent throughout
oh ok
\(\frac{a}{b}=\frac{c}{d}\iff\frac{b}{a}=\frac{d}{c}\)
assume they are not 0
ok
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