Question

how to find the modulus and argument of (1-2i)(4+3i).. steps please??

Answer 1

first simplify this :
(1-2i)(4+3i

multiply them out, or foil,
and bring it in the form of x+iy

can you do that ?

Answer 2

once you have it in x+iy form,
your modulus will be \(\large \sqrt{x^2+y^2}\) and the argument will be
\(arctan (y/x)\)

Answer 3

(1-2i)(4+3i)

start simplifying :)

Answer 4

@Ayuni did you try ?
if you're stuck in any step, i could help you.

Answer 5

Welcome to OpenStudy :) @Ayuni

Answer 6

btw, thanks @marissalovescats

Answer 7

how about this type of question;
\[\frac{ 1+5i }{ 2+i }\]
i got the final answer is \[\frac{ 9i+7 }{ i+4 }\]

Answer 8

@hartnn .. thanks anyway.. helps me a lot.