Question

The expression 2^3+ax^2+b can be divided exactly by (x+1), & its remainder is 16 when divided by (x-3). find values of a & b
@ganeshie8

Answer 1

use below :

if (x-k) is a factor of a f(x), then
f(k) = 0

Answer 2

since (x+1) is a factor of f(x),
f(-1) = 0

Answer 3

2(-1)^3+a(-1)^2+b=0
like this

Answer 4

yes, simplify.. that gives you first equation

Answer 5

-2+a+b=0

Answer 6

or

a+b = 2

Answer 7

b=2-a

Answer 8

ok..

Answer 9

use the other piece of given information to get the second equation :
` its remainder is 16 when divided by (x-3).`

Answer 10

x=3
2(3)^3+a(3)^2+b=16
b=-38-9a.........2
like this

Answer 11

yep!

Answer 12

two equations and two unknowns
you can solve them

Answer 13

Okay
Nxt question:

Answer 14

find value of k if (x+1) is a factor of 2x^3+7x^2+kx-3.Using this value k,solve the equation mentioned
sorry 4 d delay

Answer 15

Again.. as X+1 is a factor..means X+1=0..putting this value in the eqn...find the value of
K

Answer 16

Okay.Understood!

Answer 17

When this is done.. U will end up with a eqn with the absence of K.. but the presence of its value...Divide this eqn by X+1 as it is a factor....

Answer 18

Ok..Thnx

Answer 19

U will have a QUADRATIC EQUATION..U are talented enough t factorize it. Rite ?!! :P :D

Answer 20

ys

Answer 21

Nxt question:
The expression x^3-4x^2+x+6 & x^3-3x^2+2x+k have common factor.Find possible values of k

Answer 22

This Is Tricky

Answer 23

@eric_d: Please present this "Nxt question" as a new question (in the "Ask a question" box, not as something added on to a previous discussion. Thanks.

Answer 24

Done....!

Answer 25

I hd re post the question...