The argument of 1-i sqrt{3}/1+i sqrt{3}
Hey... Try Rationalising the Form to end up with irrational numbs only in the numerator part... Will Ya ?
pls explain it
is it ? \(\Huge \frac{1-i \sqrt{3}}{1+i \sqrt{3}}\)
Uh.. Rationalising includes changing the sign of the denominator and multiplyin it Up and down/.... (A+iB)/(A−iB) can be written as (A+iB)(A+iB)/(A-iB)(A+iB)
just write it into standers formula of complex numbers which is :- z=x+yi Hint multibly by \(\Huge \frac{1+i \sqrt{3}}{1+i \sqrt{3}} \)
sry typo , multibly by \(\Huge \frac{1-i \sqrt{3}}{1-i \sqrt{3}}\)
Yes... This multiplying is what is called as rationalisation
or simply subtract the arguments
argument of numerator = -pi/3 argument of denominator = pi/3 so argument of division = -pi/3 - pi/3 = -2pi/3
use the conjugacy technique. as @ganeshie8 said
WOW... Thankz @ganeshie8
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