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Mathematics 9 Online
OpenStudy (anonymous):

FAN AND MEDAL: Graph with a line going through points zero comma two point five and four comma two point five. Select the equation of the line that passes through the point (3, -1) and is parallel to the line on the graph. y = -1 y = 3 y = x -1 y = 3x - 1

OpenStudy (anonymous):

@mathmale

OpenStudy (mathmale):

Is this all one problem, Kayla, or have you posted two problems at once? Prefer just one.

OpenStudy (anonymous):

It's one

OpenStudy (anonymous):

The first sentence describes the graph that is shown.

OpenStudy (anonymous):

Could you draw out the graph? I'm really bad at picturing things in my head based off of words.

OpenStudy (mathmale):

All right. while it's not strictly necessary, graph these 2 given points and draw a line thru them. Next, calculate the slope of this li ne. Third, use the point-slope formula and the info you already have (m=the slope of the line connecting those two points) and a new point (3,-1). Which of these things can you do yourself, and with which do you need help?

OpenStudy (anonymous):

OpenStudy (mathmale):

Remember, please, no more "I'm really bad at ... " Instead, you might say, "I need more discussion to understand this particular topic: ."

OpenStudy (mathmale):

Looks good. You've correctly drawn a straight line thru the 2 given points. Look carefully at y our own graph. What is the slope of that line you've drawn?

OpenStudy (anonymous):

Well, I haven't learned much in the course due to an overwhelmingly long time with a substitute to lacked the ability, or actually the knowledge, to teach us the course information. Therefore, I do NOT know how to calculate slope. I know that there is an important equation y=mx+b and in this m= slope, but other than that, I am horribly lost...

OpenStudy (mathmale):

You can read the slope right off the graph, and for that reason you don't even need to use the slope formula. Have you a gut feeling for what slope means and what the slope of your line is?

OpenStudy (anonymous):

I'm not sure. Can you explain how to figure it out?

OpenStudy (mathmale):

Slope is an extremely important concept in algebra and calculus. Rather than go into a long explanation of what "slope" means, I'm going to give you three examples and then discuss them.

OpenStudy (anonymous):

OK

OpenStudy (mathmale):

|dw:1403450794072:dw|

OpenStudy (anonymous):

Okay. I know that that i positive slope and i know what negative slope looks like. but that is all

OpenStudy (mathmale):

Example of a line with zero slope:|dw:1403450898023:dw|

OpenStudy (anonymous):

So, in our current problem, there is a slope of 0?

OpenStudy (mathmale):

OK: you know what negative slope looks like and what it means:|dw:1403451002024:dw|

OpenStudy (anonymous):

Correct

OpenStudy (mathmale):

that's right. The slope is zero. That's all there is to it. Now you must find the equation of a new line that has ZERO slope and which passes through the given point, (3,-1). I'd suggest you use the "point-slope form of the equation of a straight line." This formula is\[y-y _{1}=m(x-x _{1})\]

OpenStudy (mathmale):

and is very, very common and thus very important to understand, know and remember.

OpenStudy (mathmale):

If\[y-y _{0}=m(x-x _{0}),\] and your slope m is zero (m=0), simplify this to reflect the fact that m=0. Write your answer here:

OpenStudy (anonymous):

What is the y and x with the 0 next to it?

OpenStudy (mathmale):

Note that the given point is (3,-1). The x-coordinate of this point is \[x _{0}=3\]and the y-coordinate of this point is \[y _{0}=-1.\]

OpenStudy (mathmale):

The notation \[(x _{0},y _{0})\] is frequently used to refer to a starting point. In this problem, Kayla, we know we have a line of slope zero (0) that passes through the point (or starting point) \[(x _{0},y _{0}): (3,-1)\]

OpenStudy (mathmale):

This point could represent "beginning location" or (time, amount of money in bank account at that time), and so on.

OpenStudy (anonymous):

Okay. So, where do I go from here?

OpenStudy (mathmale):

Please look at \[y-y _{1}=m(x-x _{1})\]First, suppose that m=0 (as it is in this particular problem). Substitute 0 for m in this equation. Write out the resulting new equation:

OpenStudy (mathmale):

Think:\[y-y _{1}=(0)(x-x _{1})\]reduces to what equation?

OpenStudy (mathmale):

Remember that zero times anything = zero.

OpenStudy (mathmale):

Kayla?

OpenStudy (mathmale):

I'll move on to other things now. When you're good and ready, please respond, ask a question, or whatever you need to do to continue moving forward. I'll answer next time I'm on OpenStudy. Great working with you.

OpenStudy (anonymous):

Remember that a vertical line |dw:1403452160047:dw| has an undefined slope.

OpenStudy (mathmale):

That's right: a vertical line does indeed have no definite slope; we say that the slope of a vertical line is "undefined." Also: the slope of a horizontal line is zero, OR, conversely, a horizontal line has a slope of zero. |dw:1403452235879:dw|

OpenStudy (anonymous):

hi

OpenStudy (mathmale):

The whole focus here is to find the equation of the line with zero slope that passes through (3,-1). kayla?

OpenStudy (anonymous):

Okay. So, for the equation, m=0, and since I only have 1 coordinate would I use \[x_{1} + x _{0} \] and \[y_{1} + y _{0}\]

OpenStudy (anonymous):

So: \[x_{3} + x _{0} \div y _{1} + y _{0}\]

OpenStudy (anonymous):

Am I on the right track?

OpenStudy (mathmale):

Kayla, as before, take the equation I gave you:\[y=y _{0}=m(x-x _{0})\]and substitute m = 0. Please do this now; it's of critical importance, and this is the 3rd time I've asked you to take this step. type out your result here.

OpenStudy (mathmale):

We agreed earlier that the line thru the 2 given points has a slope of zero. That's where "m=0" came from.

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