FAN AND MEDAL: Graph with a line going through points zero comma two point five and four comma two point five. Select the equation of the line that passes through the point (3, -1) and is parallel to the line on the graph. y = -1 y = 3 y = x -1 y = 3x - 1
@mathmale
Is this all one problem, Kayla, or have you posted two problems at once? Prefer just one.
It's one
The first sentence describes the graph that is shown.
Could you draw out the graph? I'm really bad at picturing things in my head based off of words.
All right. while it's not strictly necessary, graph these 2 given points and draw a line thru them. Next, calculate the slope of this li ne. Third, use the point-slope formula and the info you already have (m=the slope of the line connecting those two points) and a new point (3,-1). Which of these things can you do yourself, and with which do you need help?
Remember, please, no more "I'm really bad at ... " Instead, you might say, "I need more discussion to understand this particular topic: ."
Looks good. You've correctly drawn a straight line thru the 2 given points. Look carefully at y our own graph. What is the slope of that line you've drawn?
Well, I haven't learned much in the course due to an overwhelmingly long time with a substitute to lacked the ability, or actually the knowledge, to teach us the course information. Therefore, I do NOT know how to calculate slope. I know that there is an important equation y=mx+b and in this m= slope, but other than that, I am horribly lost...
You can read the slope right off the graph, and for that reason you don't even need to use the slope formula. Have you a gut feeling for what slope means and what the slope of your line is?
I'm not sure. Can you explain how to figure it out?
Slope is an extremely important concept in algebra and calculus. Rather than go into a long explanation of what "slope" means, I'm going to give you three examples and then discuss them.
OK
|dw:1403450794072:dw|
Okay. I know that that i positive slope and i know what negative slope looks like. but that is all
Example of a line with zero slope:|dw:1403450898023:dw|
So, in our current problem, there is a slope of 0?
OK: you know what negative slope looks like and what it means:|dw:1403451002024:dw|
Correct
that's right. The slope is zero. That's all there is to it. Now you must find the equation of a new line that has ZERO slope and which passes through the given point, (3,-1). I'd suggest you use the "point-slope form of the equation of a straight line." This formula is\[y-y _{1}=m(x-x _{1})\]
and is very, very common and thus very important to understand, know and remember.
If\[y-y _{0}=m(x-x _{0}),\] and your slope m is zero (m=0), simplify this to reflect the fact that m=0. Write your answer here:
What is the y and x with the 0 next to it?
Note that the given point is (3,-1). The x-coordinate of this point is \[x _{0}=3\]and the y-coordinate of this point is \[y _{0}=-1.\]
The notation \[(x _{0},y _{0})\] is frequently used to refer to a starting point. In this problem, Kayla, we know we have a line of slope zero (0) that passes through the point (or starting point) \[(x _{0},y _{0}): (3,-1)\]
This point could represent "beginning location" or (time, amount of money in bank account at that time), and so on.
Okay. So, where do I go from here?
Please look at \[y-y _{1}=m(x-x _{1})\]First, suppose that m=0 (as it is in this particular problem). Substitute 0 for m in this equation. Write out the resulting new equation:
Think:\[y-y _{1}=(0)(x-x _{1})\]reduces to what equation?
Remember that zero times anything = zero.
Kayla?
I'll move on to other things now. When you're good and ready, please respond, ask a question, or whatever you need to do to continue moving forward. I'll answer next time I'm on OpenStudy. Great working with you.
Remember that a vertical line |dw:1403452160047:dw| has an undefined slope.
That's right: a vertical line does indeed have no definite slope; we say that the slope of a vertical line is "undefined." Also: the slope of a horizontal line is zero, OR, conversely, a horizontal line has a slope of zero. |dw:1403452235879:dw|
hi
The whole focus here is to find the equation of the line with zero slope that passes through (3,-1). kayla?
Okay. So, for the equation, m=0, and since I only have 1 coordinate would I use \[x_{1} + x _{0} \] and \[y_{1} + y _{0}\]
So: \[x_{3} + x _{0} \div y _{1} + y _{0}\]
Am I on the right track?
Kayla, as before, take the equation I gave you:\[y=y _{0}=m(x-x _{0})\]and substitute m = 0. Please do this now; it's of critical importance, and this is the 3rd time I've asked you to take this step. type out your result here.
We agreed earlier that the line thru the 2 given points has a slope of zero. That's where "m=0" came from.
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