Question

PLEASE help??

The distance traveled by a falling object is given by the formula d = 0.5gt2 where d = distance, g = the acceleration due to gravity, and t = time. Solve this equation for g, and use your formula to determine the acceleration due to gravity if a baseball takes 10 seconds to hit the ground after being dropped from a height of 490 feet. Show all steps in your work.


I don't just want the answer, I want someone to help me work it out. Thanks!!

Answer 1

Given:
\[\huge d = 0.5g t^2 \]

Answer 2

g=d/(0.5*t^2)

Answer 3

\[\huge g = \frac{d}{0.5t^2}\]

Answer 4

how did you get that?

Answer 5

the g=d/(0.5*t^2), I mean

Answer 6

Dividing both side by 0.5 t^2

Answer 7

Now substitute d=490 and t 10 in the above formula

Answer 8

so it would be

d 0.5t
_____ = ______
0.5t2 0.5t2

Answer 9

and then substitute d over 0.5t2 for 490 over 10?

Answer 10

or is that wrong

Answer 11

\[\huge g= \frac{d}{0.5t^2}= \frac{490}{0.5 \times 10^2}\]
\[\huge g= \frac{490}{0.5 \times 100}= \frac{490}{50}= \frac{49}{5}\]
\[\huge g= \frac{49}{5} =9.8\]
hence g= 9.8 feet/sec^2

Answer 12

so the acceleration would be 9.8 feet/sec²?

Answer 13

Yes

Answer 14

anyways, thanks for helping!! :)