The height above the ground (in metres) of a rocket is given by the equation h(t)=-4.9t^2 +49t + 2.5 where the time (t) is measured in seconds.

a) What is the height of the rocket at 2 seconds?
b) When does the rocket achieve its maximum height?
c) what is its maximum height?

Question

The height above the ground (in metres) of a rocket is given by the equation h(t)=-4.9t^2 +49t + 2.5 where the time (t) is measured in seconds. 

a) What is the height of the rocket at 2 seconds?
b) When does the rocket achieve its maximum height?
c) what is its maximum height?

anonymous · Answer

(1) put t=2 in the equation
(2)differentitate this equation and equate it to 0 to get time to reach max. height
(3)now put the value of t obtained in 2 in h(t) to get the max. height

anonymous · Answer

a bit confused but i'll try it :) thanks

anonymous · Answer

i have written answers for different parts.. if u have any confusion in any part  please ask  :)

anonymous · Answer

I will, thank you! :)

anonymous · Answer

Refer to the attachment from Mathematica 9 Home Edition.

anonymous · Answer

this helped a lot, I understand it now thank you sooo much! :D

anonymous · Answer

Your welcome.