try converting everything into sin and cos
see if it helps simplifying the function to be integrated
hartnn (hartnn):
sec x= ...
cosec x = ..?
OpenStudy (anonymous):
1/cosx and 1/sinx
OpenStudy (anonymous):
i know trigonometry and rules of integration but ia m not able to do it.
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OpenStudy (johnweldon1993):
Right, because what we have is
\[\large \frac{\frac{1}{cos^2(x)}}{\frac{1}{sin^2(x)}}\]
which comes out to \[\large \frac{sin^2(x)}{cos^2(x)}\]
Which we know to be
\[\large \tan^2(x)\]
This integral looks alot better like
\[\large \int^{}_{} tan^2(x)dx\]
hartnn (hartnn):
so basically you just need integration of tan^2 x , right ?
hartnn (hartnn):
oh he showed you
hartnn (hartnn):
now use the pythagorean identity involving tan^2 x
OpenStudy (anonymous):
sec^2(x)-1
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OpenStudy (johnweldon1993):
Right...
hartnn (hartnn):
yes,
and you know the integration of sec^2 x
?
pretty standard
OpenStudy (anonymous):
tanx
hartnn (hartnn):
thats correct
and you must also be knowing integration of 1
OpenStudy (anonymous):
x
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