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Mathematics 7 Online
OpenStudy (i<3mybaby):

A 45 foot long escalator rises from the first floor to the second floor of a shopping mall. The escalator makes a 30° angle with the horizontal. How high above the first floor is the second floor?

OpenStudy (i<3mybaby):

A. 26 ft B. 78 ft C. 22.5 ft D. 45 ft

OpenStudy (johnweldon1993):

|dw:1403471200229:dw| So we have an angle, and the hypotenuse, and we want the opposite side from the angle Which trig function uses opposite and hypotenuse?

OpenStudy (i<3mybaby):

huh?

OpenStudy (johnweldon1993):

Hmm what grade of math are you in?

OpenStudy (i<3mybaby):

10th grade geometry

OpenStudy (johnweldon1993):

Oh okay, then we'll use the special triangles way (sorry I was doing trigonometry before)

OpenStudy (i<3mybaby):

it's okay.

OpenStudy (i<3mybaby):

its a 30, 60, 90

OpenStudy (johnweldon1993):

So what we have is a 30-60-90 triangle the side ratios that we have with that type of triangle is |dw:1403471392024:dw| So the side opposite the 30 degree angle, is our shortest leg, The side opposite the right angle, is 2 times what that length will be Since we know that long side to be 45..we know the side opposite the 30 degree angle will be half the 45...... \[\large \frac{45}{2} = 22.5\]

OpenStudy (i<3mybaby):

Omg i was right yay!

OpenStudy (i<3mybaby):

I was just double checkiung

OpenStudy (johnweldon1993):

Haha great job :)

OpenStudy (i<3mybaby):

can u help me double check like 3 more

OpenStudy (johnweldon1993):

Lol sure :)

OpenStudy (i<3mybaby):

A ladder 15 feet long leans against a wall and forms an angle of 45º with the ground. How far from the wall is the ladder? A. 15 ft B. 7.5 ft C. square root of 2 D. 7.5 square root of 2

OpenStudy (johnweldon1993):

And what did you get :P

OpenStudy (i<3mybaby):

7.5

OpenStudy (johnweldon1993):

7.5 square root of 2...close :)

OpenStudy (i<3mybaby):

yay

OpenStudy (johnweldon1993):

Because that time, the side ratios are |dw:1403473159769:dw| So we have the side that relates to the √2 To figure out the other side...we need (what number times √2 = 15 ?? So \[\large x√2 = 15\] \[\large x = \frac{15}{\sqrt{2}}\] \[\large x = \frac{15\sqrt{2}}{2}\] \[\large x = 7.5\sqrt{2}\]

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