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Prove the identity. 2cos^2 x/1-cos^2 x = 2/tan^2 x
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do you recall a trigonometric identity relating sin^2 x and cos^2 x ?
yes i do, i tried to sub in what fits to the identities but I'm still messing up
ok, so we have \(\Large \sin^2 x+\cos^2 x=1\) try to isolate sin^2 x ?
subtract cos^2 x from both sides, what u get ?
so like this? sin^2x - cos^2 x = 1-cos^2 x
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\(\Large \sin^2 x+\cos^2 x=1\) \(\Large \sin^2 x+\cos^2 x-\cos^2 x=1-\cos^2 x \) \(\Large \sin^2 x = 1-\cos^2 x\) got this ?
oh yeah i forgot the first cos^2 but yup i get it :)
so your denominator is just sin^2 x, right ?
yup :) and now from there i have to make it equal to the 2/tan^2 x?
correct
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well that was easy, thank you! :)
welcome :)
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