Question

I bet no one can solve this equation.

Answer 1

5x^-2y^10 over 2x^-1(-3x^-3y^-1)^-2

Answer 2

Because there is no equation to solve. :p

Answer 3

Do you mean to simplify the expression.

Answer 4

Yes, straight from an SAT study book

Answer 5

this is http://media.tumblr.com/tumblr_memy8mw86I1qc9tqw.gif

Answer 6

I'm going to phrase this using latex just to make sure I understand what you have written:
\[\frac{5x^{-2}y^{10}}{2x^{-1}(-3x^{-3}y^{-1})^{-2}}\]

Answer 7

@DawnR XD hahaha

Answer 8

It is very important to recall the law of exponents here.
I will write some useful ones here regarding this problem:
\[x^{-n}=\frac{1}{x^n}\]
\[\frac{1}{x^{-n}}=x^{n}\]
\[x^{1}=x\]
\[x^0=1 \text{ note: } x \neq 0\]
\[(a^rb^tc^s)n=a^{rn}b^{tn}c^{sn}\]

Answer 9

also
\[x^nx^m=x^{m+n} \text{ and } \frac{x^n}{x^m}=x^{n-m}\]

Answer 10

These are good lows to recall for this problem.

Answer 11

also that one law is a little broken let me rewrite it

Answer 12

\[(a^rb^tc^s)^n=a^{rn}b^{tn}c^{sn}\]

Answer 13

can you use this last law here on the problem anywhere that you can see?

Answer 14

I'm not asking this question because I need help, I am asking to see if someone for actually get it

Answer 15

Can*

Answer 16

I will give you a hint:

look in the circle below: