indicate the equation of the given line in standard form. The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)
The given line is in the point-slope form, passing through the point (3,4). If we replace (3,4) by (1,-2), that will be the required equation of the new line after converting it to standard form.
so replace (3,4) with (1,-2)? then solve?
Right!
A line in point slope form has the equation: \[(y-y_1=m(x-x_1)\] where m is the slope, and \[(x_1,y_1)\] is the point though which the line passes.
so y+2=2/3(x-1)?
?
Yes, the first step is correct. Well done! Now solve for y to put it in standard form.
how do i do that?!!!!
Start with \[y+2=\frac{2}{3}(x-1)\] can you expand the right-hand side?
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