Question

How can x2 = x2 + 2x + 9 be set up as a system of equations?

y = x2 - 9
y = x2 + 2x + 9


y = x2
y = x2 + 2x + 9

y = x2 + 2x
y = x2 + 9

y = x2
y = 2x + 9

Answer 1

@ikram002p

Answer 2

what do u think ?

Answer 3

the first one, but i dont feel like im right

Answer 4

yeah its not right , ill tell u how to make sure

Answer 5

\(x^2 = x^2 + 2x + 9\)
so
take each side as equation it self

Answer 6

\(y= x^2 + 2x + 9=x^2\)
so
\(y= x^2 + 2x + 9 \)
\(y= x^2\)

Answer 7

allright, so its either the second or last

Answer 8

Note that you now have two equations that begin with "y=", and as such you have a set of simultaneous equations (a system of equations) that are to be solved for both x and y.

To answer your question: NO. It's not a matter of "either...or" here. You still need both equations to find a solution. A solution, if it exists, is a point that is common to both functions / graphs.

Answer 9

check the last one
its
\(y=x^2\)
\(y=2x +9\)
so
\(x^2=2x+9\)
is it true ?

Answer 10

no

Answer 11

so what do u think nw ?
what the answer might be ?

Answer 12

i dont know, im a little confused now

Answer 13

Please hold on for a moment. I don't think it appropriate to ask, "is it true," in regard to the equation\[x^2=2x+9.\]This equation is not (and was not supposed to be) an identity, but rather a conditional equality. "conditional" in this case means taht the equation is true only for certain x values. Your job is to determine what those values are.

Answer 14

^_^

Answer 15

Here's a quick summary:

x2 = x2 + 2x + 9 is given. For now, forget about "setting this up as a system of equations."

Subtracting x^2 from both sides, 0=2x+9, or 2x=-9, or x= ???

Answer 16

In other words, solve 2x=-9 for x.

Answer 17

Sorry, I need to go elsewhere. Glad to be of help, but I do hope for reasonably quick responses to my posts. Perhaps later?