Question

The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5).

y = 5x − 15

y = 5x + 15

y = 1 over 5x + 21 over 5

y = 1 over 5x − 29 over 5

Answer 1

Do you know what the slope of y=5x+1 is?

Answer 2

@dan815 i dont:?

Answer 3

y=mx+b <--- equation of a line m is slope, b is y-intercept

Answer 4

so what do you think the slope of
y=5x+1 is

Answer 5

Im sorry i have no idea im so lost);

Answer 6

you see how the m is the slope and its right before the x

Answer 7

similarly in
y=mx+b
y=5x+1 <----- the 5 is in the place of m, so the 5 is the slope

Answer 8

ok?

Answer 9

the slope on a parallel line is the same so m=m
but the y-intercept is different so b on the 1st equation is different from the second
basic equation being: y=mx+b

Answer 10

dan you still marked the bad line as parallel

Answer 11

so the equation you are looking for starts off
y=5x
figure out where b is compared to the slope and where it crosses the y-axis

Answer 12

Do you know how to use point slope form?

Answer 13

no i follow my own notation that arrow in the middle is equivalent to putting 2 arrow heads on the ends of the line saying they are continued for all x

Answer 14

To write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5) I would use point slope form. A line that is parallel will have the same slope. The line y = 5x + 1 has a slope of 5. Use the point (4,5) with the point slope form to find a line that is parallel.