Question

Question

Answer 1

\[\frac{ b+2 }{ 2b^2-b-1 } - \frac{ 1 }{ b-1 }\]

A. −1/2b+1
B. −b+1/(2b+1)(b−1)
C. b+1/(2b+1)(b−1)
D. b+1/2b^2

Answer 2

Facor 2b^2-b-1 first

Answer 3

How?

Answer 4

(2b+1)(b-1) = (2b*b)-2b+b-1 = 2b^2-b-1

Answer 5

yup

Answer 6

:)

Answer 7

\[\frac{ b+2 }{ (2b+1)(b-1) } - \frac{ 1 }{ (b-1) }\]

This is the new eqation

Answer 8

\(\Large \frac{ b+2 }{ 2b^2-b-1 } - \frac{ 1 }{ b-1 }\)
\(\Large =\frac{ b+2 }{ (2b+1)(b-1) } - \frac{ 1 }{ (b-1) }\)
\(\Large =\frac{ b+2 }{ (2b+1)(b-1) } - \frac{2b+1}{(2b+1)(b-1)}\)
\(\Large =\frac{b+2-2b-1}{(2b+1)(b-1)}\)
\(\Large =\frac{-(b-1)}{(2b+1)(b-1)}=\color{blue}{\frac{-1}{2b+1} }\)