5.25 mL of an unknown HCl sample is titrated with 25.3 mL of a 0.00100 M solution of NaOH to its equivalence point, what is the initial concentration of the acid?

Question

anonymous · Answer

@aaronq @sweetburger

anonymous · Answer

@seehearcreate

anonymous · Answer

Choices:
2.08*10^-2 M
4.82*10^-3 M
8.28*10^-4 M
4.64*10^-3 M

anonymous · Answer

I'd help you with this but I'm dealing with the same stuff so I'm not quite certain of myself haha!

abmon98 · Answer

Construct a balanced equation
NaOH+HCl-->NaCl+H2O
Number of moles=Volume*concentration
Number of moles of NaOH=(25.3/1000)*0.00100
Number of moles of NaOH=0.0000253 moles 
Ratio of moles of NaOH to HCl is 1:1
0.0000253=5.25/1000*concentration
1000*0.0000253/5.25=0.004819 when rounded we get 0.00482 so out of the choices i choose the second one

anonymous · Answer

Ok I was thinking the 2nd or 4th but I really had no idea so I'm gonna go with yours since you set it up. Thank you!!!

anonymous · Answer

And you're right :) Thank you SO much!

abmon98 · Answer

Your most welcome :)