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Express 5t in terms of the base 2 exponential function
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\[f(t)=5^t\] like that?
and you want to use the base \(2\) rather than \(5\) ?
yes
only thing i can think of is to solve \[5^x=2\] for \(x\)
by the change of base formula you get \[x=\frac{\ln(2)}{\ln(5)}\] making \[\large 5^{\frac{\ln(2)}{\ln(5)}}=2\] and so \[\left(\large 5^{\frac{\ln(2)}{\ln(5)}}\right)^t=2^t\]
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oh but maybe that is backwards!
yes, it is backwards i think solve \[2^x=5\] so \[x=\frac{\ln(5)}{\ln(2)}\]etc etc
was thinkinking the same, i am pretty confused...i hate it when math problems are worded, but thanks
yeah, it is confusing but i think what you want is \[\left(\large 2^{\frac{\ln(5)}{\ln(2)}}\right)^t=5^t\]
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