square root of 75 over 2 + 3 square root of 2 over 4 =?
Is this the question? \( \dfrac{\sqrt{75}}{2} + \dfrac{3 \sqrt{2}}{4} = \)
Yes.
You need to add two fractions. What do two fractions that are to be added need to have?
Uh, Idk?
A common denominator.
The denominators are 2 and 4. What is the LCD of 2 and 4?
2?
No. The LCD is the "least common denominator." That means the smallest number that you can divide by both numbers evenly (without remainder). The LCD of 2 and 4 is 4, since 4 is the smallest number divisible by both 2 and 4.
The right fraction already has the LCD. Now we need the LCD in the left fraction.
Okay
\(\dfrac{\sqrt{75}}{2} + \dfrac{3 \sqrt{2}}{4} =\) \(=\dfrac{2}{2} \times \dfrac{\sqrt{75}}{2} + \dfrac{3 \sqrt{2}}{4} \) \(=\dfrac{2\sqrt{75}}{4} + \dfrac{3 \sqrt{2}}{4} \) Now that we have the same denominator, we can add the fractions.
alright.
Now we add the fractions.
how?
\(=\dfrac{2\sqrt{75}}{4} + \dfrac{3 \sqrt{2}}{4}\) \(= \dfrac{ 2\sqrt{75} + 3 \sqrt{2}}{4}\) Now we can do one final step. We can simplify \(\sqrt{75} \).
\(= \dfrac{ 2\sqrt{25 \times 3} + 3 \sqrt{2}}{4}\) \(= \dfrac{ 2\sqrt{25} \times \sqrt {3} + 3 \sqrt{2}}{4}\) \(= \dfrac{ 2 \times 5\sqrt {3} + 3 \sqrt{2}}{4}\) \(= \dfrac{ 10\sqrt {3} + 3 \sqrt{2}}{4}\)
How did you get that?
I did it step-by-step. Just go over it a few times until you understand it.
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