Question

Medal and fan

Suppose you have the solutes NaF and HF (Ka for HF is 7.2*10^-4). Explain the effect of adding NaF to an equilibrium solution of HF.

Thankyou(:

Answer 1

@Abhisar Could you help me please?(:

Answer 2

What do you think ?

Answer 3

Ka = [H\(^{+}\)][F\(^{-}\)] = 7.2*10\(^{-4}\)

Answer 4

Now when u will add NaF, [F\(^-\)] will increase

Answer 5

Can u guess now what will be the answer ?

Answer 6

Then since there will be more fluorine ions in the solution that the pH would actually increase since the ration of F to H is 2:1?

Answer 7

Have u learnt Le chatelier's principle ?

Answer 8

That when something is added to the system and offsets the equilibrium that the system will produce more of the product and therefore will shift to the right to maintain equilibrium?

Answer 9

Yep,
It's a principle stating that if a constraint (such as a change in pressure, temperature, or concentration of a reactant) is applied to a system in equilibrium, the equilibrium will shift so as to tend to counteract the effect of the constraint.

Answer 10

Here we r adding products (F-), so the equilibrium will shift towards the left and hence will be lowered

Answer 11

got it ?

Answer 12

Sorry, I realized now that the equation called for products and not reactants. It's almost 2am haha, I'm quite tired. That makes sense, thankyou very much.

Answer 13

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