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Chemistry 13 Online
OpenStudy (anonymous):

12. Which of the following are redox reactions? Name the reducing agent in each redox reaction. a) H2 + Cl2 → 2 HCl b) 2Li + F2 →2LiF c) 2NaOH + H2SO4 → Na2SO4 + 2H2O d) Fe2O3 + CO → Fe + CO2

OpenStudy (anonymous):

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OpenStudy (somy):

Do you know how to find oxidation states of element??

OpenStudy (somy):

tell me what you do know about redox reactions so that i get the idea and help you out in solving this question :)

OpenStudy (somy):

r u there?

OpenStudy (anonymous):

yes

OpenStudy (somy):

alright so what do u want me to explain? do u know whats redox reaction?

OpenStudy (anonymous):

redox reaction involves transfer of electrons

OpenStudy (anonymous):

i don't know how to work out the answers

OpenStudy (anonymous):

can you show me how to do the first one, and i'll try and learn from that

OpenStudy (somy):

yes, basically its oxidation and reduction reaction taking place in 1 reaction

OpenStudy (somy):

sure :)

OpenStudy (somy):

alright here is first reaction H2 + Cl2 → 2 HCl

OpenStudy (somy):

can u tell me what's H2's and Cl2's oxidation states?

OpenStudy (anonymous):

i kinda forgot how to do that :(

OpenStudy (somy):

okay np :)

OpenStudy (anonymous):

would you mind explaining how to find

OpenStudy (somy):

when the element is given on its OWN meaning alone, whether its Cl2 or Na or whatever its oxidation state would be 0

OpenStudy (anonymous):

okay

OpenStudy (somy):

so if u were given hmm lets say O2 what would be its oxidation state?

OpenStudy (anonymous):

so H2 and CI2 is 0

OpenStudy (anonymous):

0

OpenStudy (somy):

yes :)

OpenStudy (somy):

good next we go to product which is 2 HCl

OpenStudy (anonymous):

so if its NaCl it wouldn't be 0

OpenStudy (somy):

no no no

OpenStudy (anonymous):

yup

OpenStudy (somy):

i said ELEMENT not compound

OpenStudy (somy):

NaCl is compound and consists of 2 elements Na and Cl thus both would have oxidation states of something when Na or Cl2 are given alone only at that time oxidation state is 0

OpenStudy (anonymous):

so when would its oxidation state be not 0

OpenStudy (anonymous):

okay

OpenStudy (somy):

good :) so now we look at HCl

OpenStudy (anonymous):

yup

OpenStudy (somy):

HCl is a compound thus each element in it would have its oxidation state

OpenStudy (anonymous):

ok

OpenStudy (somy):

now u actually CAN say that oxidation state would be 0 i'll show how

OpenStudy (anonymous):

okie

OpenStudy (somy):

when i say 0 i mean TOTAL of oxidation states of all element IN a compound is = 0

OpenStudy (anonymous):

okay

OpenStudy (somy):

so as you see HCl doesn't have any specificity in its total oxidation state meaning it doesn't look like this \[HCl ^{-}\] or something like that

OpenStudy (anonymous):

yup

OpenStudy (somy):

as long as a compound does not have this it's total oxidation state will always be 0 same goes to element alone actually so if Cl is not given as just Cl2 or Cl but it's given like this \[Cl ^{-}\] its oxidation state would be -1

OpenStudy (somy):

not 0 :)

OpenStudy (anonymous):

yup

OpenStudy (somy):

so now lets see whats oxidation state of each element in HCl compound

OpenStudy (somy):

there some elements that have ALWAYS same oxidation state H is one of them and its oxidation state in a compound is ALWAYS +1

OpenStudy (somy):

get it?

OpenStudy (anonymous):

yes :)

OpenStudy (somy):

ok so lets see we said that total oxidation state of a compound would be 0 and we know oxidation state of H which is +1 so we can write it in a mathematical form (+1) + X = 0 X is representing oxidation state of Cl

OpenStudy (somy):

so what would be X oxidation state? solve it :)

OpenStudy (anonymous):

-1

OpenStudy (somy):

bingo :)

OpenStudy (anonymous):

would it be 0, since x = 0/1 ?

OpenStudy (somy):

no no look (+1)+X = 0 its ADDITION not multiplication thus +1+X= 0 X= 0-1 X= -1

OpenStudy (anonymous):

i wasn't sure due to the brackets

OpenStudy (anonymous):

i understand it now :)

OpenStudy (somy):

i wrote bracket so that u see that it was oxidation state lol

OpenStudy (somy):

coz it was +1 right?

OpenStudy (anonymous):

yep

OpenStudy (somy):

okay now H2 oxidation state before the reaction was 0 and Cl2 oxidation state before reaction is 0

OpenStudy (anonymous):

yes

OpenStudy (somy):

now we found H and Cl's oxidation states AFTER reaction in a compound what are they?

OpenStudy (anonymous):

+1 and -1

OpenStudy (somy):

good so for H2 u see change from 0 to +1 for Cl2 u see change from 0 to -1

OpenStudy (anonymous):

yup

OpenStudy (somy):

negative sign means GAIN of electron positive sign means LOSS of electron right?

OpenStudy (anonymous):

right

OpenStudy (somy):

when something GETS OXIDIZED it will gain electron and when something GETS REDUCED it loses electron

OpenStudy (anonymous):

yeah

OpenStudy (somy):

now question DO YOU SEE BOTH happening?

OpenStudy (anonymous):

yes

OpenStudy (somy):

0 to +1 meaning Loses 1 electron 0 to -1 meaning gains 1 electron

OpenStudy (somy):

so both oxidation and reduction happen in this 1 reaction right?

OpenStudy (anonymous):

right

OpenStudy (somy):

now their question is ame the reducing agent in each redox reaction.

OpenStudy (somy):

name*

OpenStudy (anonymous):

so the first one question is a redox reaction

OpenStudy (somy):

yes it is :)

OpenStudy (anonymous):

so whats the reducing agent?

OpenStudy (somy):

OIL RIG Oxidation is loss of electron, this electron is LOST by the thing that is being oxidized Reduction is gain of electron, this electron is gained by the thing that is being reduced so that means OXIDIZING agent would Gain electron and REDUCING agent would Lose electron

OpenStudy (anonymous):

Cl2 is the reducing agent then?

OpenStudy (somy):

So in other wards Oxidizing agent - OXIDIZED OTHER AND REDUCES ITSELF meaning oxidized compound/element would LOSE electron and oxidizing agent would take that electron Thus get reduced

OpenStudy (somy):

we said Reducing agent LOSES electron

OpenStudy (somy):

Cl2 is changing form 0 to -1 meaning it GAINS electron

OpenStudy (somy):

do u get it??

OpenStudy (anonymous):

oh okay so its H2

OpenStudy (somy):

yup :)

OpenStudy (anonymous):

Thanks for all your help, you explain really well!! Your Amazing :)

OpenStudy (somy):

you are welcome :)) i just want to confirm if u got everything maybe lets do other equation? just to check out

OpenStudy (anonymous):

sure :)

OpenStudy (anonymous):

2Li = 0

OpenStudy (anonymous):

F2=0

OpenStudy (anonymous):

2LiF = 0

OpenStudy (somy):

okay i was gonna suggest doing the hard one but ok finish this one

OpenStudy (anonymous):

will do the hard one

OpenStudy (somy):

nah finish this one first :)

OpenStudy (anonymous):

is Q C or D the difficult one?

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