Question

9. Write the balanced equation for the reaction between
a) I2 → 2I- + 2e- and Li → Li+ + e-
b) Mg → Mg2+ + 2e- and O2 → 2H2O
c) Ag → Ag+ + e- and PbO2 → Pb2+
10. Calculate the emf produced by the above reactions

Answer 1

idk this one maybe @Abhisar can help

Answer 2

okie

Answer 3

Sorry m also not sure

Answer 4

thanks for trying

Answer 5

i wonder if they are asking for this kind of reaction

I2 → 2I- + 2e- and Li → Li+ + e-

I2 + 2Li ---> 2LiI

Answer 6

yes i think you are correct @Somy , since the question given indicates two half reactions

Answer 7

wait i got it

Answer 8

mm?

Answer 9

The equations given in the question are two half equations of an electrochemical equation
1)I2 → 2I- + 2e- and Li → Li+ + e-
\(\bf Solution\)
Multiply the second equation with 2 and reverse it. Then add it to the first equation. We will get
I\(^2\) + 2I → 2I\(^-\) + 2Li\(^+\)

Answer 10

*equation = reaction

Answer 11

got it ?

Answer 12

u wrote something wrong in the reaction

Answer 13

yes i know..it's a typo..LOL
I2 + 2Li ---> 2I- + 2LI+

Answer 14

clear now ?

Answer 15

Thank you :)

Answer 16

\(\color{red}{\huge\bigstar}\huge\text{You are Most Welcome! }\color{red}\bigstar\)
\(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)

Answer 17

For question b, is it the same?

Answer 18

~_~ its same as i wrote tho @Abhisar

Answer 19

but q is how to find Emf

Answer 20

yes, i said u were correct. but u wrote it in a combined way

Answer 21

0.54 - (-3.05) = 3.59\(\approx\)3.6 V

Answer 22

Is this the answer for 1st one ?

Answer 23

I don't have the answers :(

Answer 24

Hmmm..i think i am most probably correct !

Answer 25

i'll tell u how i calculated it

Answer 26

would you mind showing me how to do q b as well please?

Answer 27

E\(_{cell}\)=E\(_{Reduced}\)-E\(_{Oxidised}\)

Answer 28

In the equation I is reduced and Li is oxidised

Answer 29

got upto this ?

Answer 30

yes

Answer 31

whats next?

Answer 32

Now from standard Electrode potential table E I = 0.54 & E Li = -3.05

Answer 33

Substitute the values and find the answer

Answer 34

Now can u do the second one ?

Answer 35

which is oxidized and which is reduced in the second one?

Answer 36

In general the one which looses electron gets oxidised and the one who gains electron gets reduced.

Answer 37

so Mg → Mg2+ + 2e- oxidizes
O2 → 2H2O reduction

Answer 38

Mg - oxi
O2 - red

Answer 39

standard Electrode potential table E Mg = 2.37 & E 02 = -0.40

Answer 40

= -2.77

Answer 41

is that right @Abhisar

Answer 42

yes i think so

Answer 43

bt not sure, so do cross check it with othrs

Answer 44

sure