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Mathematics 10 Online
OpenStudy (luigi0210):

Sequences~

OpenStudy (luigi0210):

Determine whether \(\Large a_{n}={\frac{3+5n^2}{n+n^2}}\) diverges or converges. Also determine the sequence's tendency and find it's bounds

OpenStudy (luigi0210):

@ganeshie8 ?

OpenStudy (somy):

@iambatman @ikram002p

OpenStudy (somy):

@thomaster

OpenStudy (somy):

@ParthKohli

OpenStudy (ikram002p):

so what test did u try ?

OpenStudy (somy):

@Ashleyisakitty

OpenStudy (luigi0210):

I have had no practice in this area so sorry if Idk what you're talking about.. but I did the divergence test.

OpenStudy (ikram002p):

do u think its diverge or converge ? (are you familier with comparasion test or ratio test ?)

ganeshie8 (ganeshie8):

this is just a sequence right ? @ikram002p

OpenStudy (ikram002p):

yes mm so ?

OpenStudy (luigi0210):

It diverges since the limit was not 0.. And I know the ratio test

ganeshie8 (ganeshie8):

looks we're mixing sequence and series

OpenStudy (ikram002p):

ohhh , ok i got ur point but i was thinking if the series was converge then the seqence is converge as well

OpenStudy (ikram002p):

but finding the limit as a_n goes to infinity would be better , sry my bad lol

ganeshie8 (ganeshie8):

yes !

OpenStudy (luigi0210):

So based on the sequence test.. since it doesn't go to \(\infty\) it converges?

ganeshie8 (ganeshie8):

yes \(\large \lim \limits_{n\to \infty }a_{n}=\lim \limits_{n\to \infty }{\dfrac{3+5n^2}{n+n^2}} = \dfrac{5}{1}\)

ganeshie8 (ganeshie8):

since the limit exists, the sequence converges.

OpenStudy (luigi0210):

How would I find it's tendencies and bounds?

ganeshie8 (ganeshie8):

\[\large A \le \dfrac{3+5n^2}{n+n^2} \le B\]

ganeshie8 (ganeshie8):

I'm also not sure what they mean by `tendencies`, but we can try finding the bounds ^ @ikram002p help

ganeshie8 (ganeshie8):

we already have the upper bound \[\large A \le \dfrac{3+5n^2}{n+n^2} \lt 5\]

ganeshie8 (ganeshie8):

@dan815

OpenStudy (dan815):

Luigi what does it mean tendency?

OpenStudy (ikram002p):

tendencies is the limit when n goes to infinity bounded for sure 0<a_n<=5 mmm u can found another lower bound

OpenStudy (dan815):

the mean of the sequence?

OpenStudy (dan815):

oh ok

OpenStudy (ikram002p):

@ganeshie8 so what do you think ? n should be integer right ? no need to minimize since its monotone \(a_1=4\) and upper bound 5

OpenStudy (ikram002p):

so 4<=a_n<5 right ?

ganeshie8 (ganeshie8):

yes its a monotone sequence for n > 3 check a_2 once

OpenStudy (ikram002p):

3.8

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