4. Draw a fully labelled electrochemical sell with the half-cells consisting of:
a) Ag│AgNO3 and Mg│Mg(NO3)2
b) Sn│Sn(NO3)2 and Zn│Zn(NO3)2
c) Calculate the amount of voltage put out by the above reactions

Question

4.	Draw a fully labelled electrochemical sell with the half-cells consisting of:
a)	Ag│AgNO3 and Mg│Mg(NO3)2
b)	Sn│Sn(NO3)2 and Zn│Zn(NO3)2
c)	Calculate the amount of voltage put out by the above reactions

chmvijay · Answer

yaaa u can draw where are u finding the problem ?

anonymous · Answer

can you do the first one so i have an idea

chmvijay · Answer

Ag has the higher reduction potential meaning Ag+ ions will be reduced to Ag 
and mg will oxidise ( see electrochemical potentail series values)
Ag+(aq) + e- --> Ag(s) E = 0.7996V (0.8V) - reduction half cell
Mg(s) --> Mg2+(aq) + 2e- E = 2.37V - oxidation halff cell

overall reaction
2Ag+(aq) + Mg(s) --> 2Ag(s) + Mg2+(aq) 

EMF is the sum of the reduction and oxidation potentials 
EMF = 0.8 + 2.37 
= 3.17V |dw:1403525168808:dw|