Question

Simplify:

Answer 1

Simplify what?

Answer 2

Sorry one moment

Answer 3

\[(1-\cos \Theta)(1+\cos \Theta)\div(1-\sin \Theta)(1+\sin \Theta)\]

Answer 4

The first is actually over the second like this:

Answer 5

Are you able to help?

Answer 6

What level of math is this?

Answer 7

Trig

Answer 8

The class is Algebra 2 but it's in trig.

Answer 9

O.O so thats what i have to look forward to..... i'm in geometry lol

Answer 10

Yeah it sucks.

Answer 11

Yeah... so does geometry.. i hate i >.< i wish all math was like algebra

Answer 12

\[(1-\cos \theta)(1+\cos \theta)=1-\cos ^{2}\]

Answer 13

and the same for sin

Answer 14

My options are:
sin^2Theta
cos^2Theta
tan^2Theta
cosTheta/sinTheta

Answer 15

So, if I were to do that I would get:
1-cos^2 over 1-sin^2

but that fits none of my options.

Answer 16

right
1-cos^2 theta=sin^2 theta
1-sin^2theta=cos^2theta

Answer 17

Ok so would it be cosTheta/sinTheta?

Answer 18

sin/cos
not cos/sin

Answer 19

There is no option for that though.

Answer 20

\[\frac{ \sin ^{2}\theta }{ \cos ^{2}\theta }=\tan ^{2}theta\]

Answer 21

Oh ok. Thank you very much.

Answer 22

any time :)