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Express the complex number in trigonometric form. -2i
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In order to use the trigonometric form, of a complex number z, find its modulus r and its argument theta, \[z=r(\cos\theta+i\sin\theta)\]
For a pure negative imaginary number, you know that theta is 3pi/2. In this case, also, the modulus is easy because is 2. So the trigonometric representation is, \[z=2(\cos(3\pi/2)+i\sin(3\pi/2))\]
2(cos 270° + i sin 270°) Would be correct then?
Perfect.
Thank you sir :p @John_ES
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