Mathematics
8 Online
OpenStudy (anonymous):
Factor this expression. Check by multiplying factors.
ac - 5ad - 5bc + 25bd
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OpenStudy (redohawk):
is it multiple choice?
OpenStudy (anonymous):
Nope.
OpenStudy (mathmate):
Rewrite as
\[(ac-5ad) - (5bc-25bd)\]
then factorize each of the two groups and see what you get.
OpenStudy (anonymous):
I'm not sure how to do that for this problem..
@mathmate
OpenStudy (mathmate):
have you learned grouping?
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OpenStudy (anonymous):
No, not yet.
OpenStudy (mathmate):
How about taking out factors?
OpenStudy (anonymous):
I haven't even learned factoring its self..
OpenStudy (mathmate):
Have you started reading about factoring?
OpenStudy (anonymous):
Nope. :/
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OpenStudy (anonymous):
I learn better by doing.. D; Can you help step by step?
OpenStudy (anonymous):
@mathmate
OpenStudy (mathmate):
Start by factoring
ac-5ad
OpenStudy (anonymous):
And how do you do that?
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OpenStudy (anonymous):
a(5d-c)?
OpenStudy (mathmate):
You see "a" is common between the two terms ac and -5ad.
This is a common factor.
Same idea as finding HCF of 10 and 15, where 5 is a common factor.
OpenStudy (anonymous):
Alright, I'm following.
OpenStudy (anonymous):
So what's next?
OpenStudy (mathmate):
Now can you do the second part?
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OpenStudy (mathmate):
-(5bc-25bd)=?
OpenStudy (anonymous):
Not by myself, I can try the work but I need somebody to correct me on my mistakes.
OpenStudy (mathmate):
If you try it, I can tell you if you did it right.
OpenStudy (anonymous):
5b(5d-1c)?
OpenStudy (mathmate):
Multiply out to see if yo
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OpenStudy (mathmate):
you get back what was there before?
OpenStudy (anonymous):
Okay, and exactly how do I do that?
OpenStudy (mathmate):
That is the reverse of factoring.
OpenStudy (anonymous):
Alright so, 5b(5d) = 25bd 5b(-1c)= -5bc
OpenStudy (mathmate):
Good, now can you piece the two together and see what it looks like?
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OpenStudy (mathmate):
I mean the first factoring part, and the second, that would add up to your original question.
OpenStudy (anonymous):
What was the first part? I never got to answer it.
OpenStudy (anonymous):
ac - 5ad = a(5d-c)?
OpenStudy (anonymous):
So that means a(5d-c)-5b(5d-1c)?
OpenStudy (mathmate):
Yes. Very good.
Knowing that you could write (5d-1c) as (5d-c), what do you notice?
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OpenStudy (anonymous):
the understood 1.
OpenStudy (mathmate):
Can you rewrite the expression without the "understood 1"?
OpenStudy (anonymous):
a(5d-c)-5b(5d-c)
OpenStudy (mathmate):
Do you notice anything in terms of common factors?
OpenStudy (anonymous):
The signs? The 5? I dunno what I'm supposed to be looking at o_o
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OpenStudy (mathmate):
Do you see that (5d-c) is common to the first and second parts?
OpenStudy (anonymous):
OH! Yes I do.
OpenStudy (mathmate):
How do you think it might help you?
OpenStudy (anonymous):
Umm.... To be honest I have no idea sir..
OpenStudy (anonymous):
But that answer is right?
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OpenStudy (anonymous):
a(5d-c)-5b(5d-c)?
OpenStudy (mathmate):
I would take out the common factor one more time!
OpenStudy (anonymous):
The 5d-c?
OpenStudy (mathmate):
yep
OpenStudy (anonymous):
Okay a(5d-c)-5b(5d-c) 25d-c^2?
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OpenStudy (mathmate):
For example,
2(x+4)-3y(x+4) = (x+4)(2-3y)
Get the idea?
OpenStudy (anonymous):
(5d-c)(a-5b)? Wut? That last one confused me
OpenStudy (mathmate):
This is perfect!
Congrats!
OpenStudy (anonymous):
Wait omg :OO! I got it right? o_o
OpenStudy (anonymous):
What's the answer omg I posted like 50 answers