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Mathematics 8 Online
OpenStudy (anonymous):

Factor this expression. Check by multiplying factors. ac - 5ad - 5bc + 25bd

OpenStudy (redohawk):

is it multiple choice?

OpenStudy (anonymous):

Nope.

OpenStudy (mathmate):

Rewrite as \[(ac-5ad) - (5bc-25bd)\] then factorize each of the two groups and see what you get.

OpenStudy (anonymous):

I'm not sure how to do that for this problem.. @mathmate

OpenStudy (mathmate):

have you learned grouping?

OpenStudy (anonymous):

No, not yet.

OpenStudy (mathmate):

How about taking out factors?

OpenStudy (anonymous):

I haven't even learned factoring its self..

OpenStudy (mathmate):

Have you started reading about factoring?

OpenStudy (anonymous):

Nope. :/

OpenStudy (mathmate):

You may want to start getting familiar with simple factoring. You can read up on it, for example, http://www.mathsisfun.com/algebra/factoring.html

OpenStudy (anonymous):

I learn better by doing.. D; Can you help step by step?

OpenStudy (anonymous):

@mathmate

OpenStudy (mathmate):

Start by factoring ac-5ad

OpenStudy (anonymous):

And how do you do that?

OpenStudy (anonymous):

a(5d-c)?

OpenStudy (mathmate):

You see "a" is common between the two terms ac and -5ad. This is a common factor. Same idea as finding HCF of 10 and 15, where 5 is a common factor.

OpenStudy (anonymous):

Alright, I'm following.

OpenStudy (anonymous):

So what's next?

OpenStudy (mathmate):

Now can you do the second part?

OpenStudy (mathmate):

-(5bc-25bd)=?

OpenStudy (anonymous):

Not by myself, I can try the work but I need somebody to correct me on my mistakes.

OpenStudy (mathmate):

If you try it, I can tell you if you did it right.

OpenStudy (anonymous):

5b(5d-1c)?

OpenStudy (mathmate):

Multiply out to see if yo

OpenStudy (mathmate):

you get back what was there before?

OpenStudy (anonymous):

Okay, and exactly how do I do that?

OpenStudy (mathmate):

That is the reverse of factoring.

OpenStudy (anonymous):

Alright so, 5b(5d) = 25bd 5b(-1c)= -5bc

OpenStudy (mathmate):

Good, now can you piece the two together and see what it looks like?

OpenStudy (mathmate):

I mean the first factoring part, and the second, that would add up to your original question.

OpenStudy (anonymous):

What was the first part? I never got to answer it.

OpenStudy (anonymous):

ac - 5ad = a(5d-c)?

OpenStudy (anonymous):

So that means a(5d-c)-5b(5d-1c)?

OpenStudy (mathmate):

Yes. Very good. Knowing that you could write (5d-1c) as (5d-c), what do you notice?

OpenStudy (anonymous):

the understood 1.

OpenStudy (mathmate):

Can you rewrite the expression without the "understood 1"?

OpenStudy (anonymous):

a(5d-c)-5b(5d-c)

OpenStudy (mathmate):

Do you notice anything in terms of common factors?

OpenStudy (anonymous):

The signs? The 5? I dunno what I'm supposed to be looking at o_o

OpenStudy (mathmate):

Do you see that (5d-c) is common to the first and second parts?

OpenStudy (anonymous):

OH! Yes I do.

OpenStudy (mathmate):

How do you think it might help you?

OpenStudy (anonymous):

Umm.... To be honest I have no idea sir..

OpenStudy (anonymous):

But that answer is right?

OpenStudy (anonymous):

a(5d-c)-5b(5d-c)?

OpenStudy (mathmate):

I would take out the common factor one more time!

OpenStudy (anonymous):

The 5d-c?

OpenStudy (mathmate):

yep

OpenStudy (anonymous):

Okay a(5d-c)-5b(5d-c) 25d-c^2?

OpenStudy (mathmate):

For example, 2(x+4)-3y(x+4) = (x+4)(2-3y) Get the idea?

OpenStudy (anonymous):

(5d-c)(a-5b)? Wut? That last one confused me

OpenStudy (mathmate):

This is perfect! Congrats!

OpenStudy (anonymous):

Wait omg :OO! I got it right? o_o

OpenStudy (anonymous):

What's the answer omg I posted like 50 answers

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