Question

Eliminate the parameter.

x = t + 4, y = t^2

Answer 1

can you solve for t, using the first equation?

Answer 2

I honestly have no idea what I'm doing.

Answer 3

Okay so these are the answer choices:
y = square root of x + x + 4
y = square root of quantity x minus four
y = x2 + 16
y = x2 - 8x + 16

I'm thinking it's y = sqrt x-4 because with the first equation, t = x-4. And sqrt x-4 makes sense to me because of this. Am I completely wrong or?

Answer 4

Well all we do is solve for 't' in the first equation

\[\large x = t + 4\] will become
\[\large t = x - 4\]

Now all we do is plug that into our second equation wherever we see a 't'

\[\large y = t^2\]
will then become
\[\large y = (x - 4)^2\]

And just distribute that out and you will have your answer

Answer 5

So y = x^2 + 16?

Answer 6

Not quite

You dont just apply the exponent to both terms...you expand

\[\large (x-4)^2 = (x - 4)(x - 4)\]

Answer 7

Then you distribute

\[\large x^2 - 4x - 4x + 16\]
\[\large x^2 - 8x + 16\]