In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg(OH)2 is made?
A. The amount of MgCl2 + KOH
B. The amount of KCl
C. The amount of MgCl2
D. The amount of KOH

Question

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg(OH)2 is made?
 	        A. 	The amount of MgCl2 + KOH
  		B. 	The amount of KCl
  		C. 	The amount of MgCl2
  		D. 	The amount of KOH

anonymous · Answer

Look at the mole ratio in the balanced equation. Two moles of potassium hydroxide are required for each one mole of magnesium chloride.

Now look at how many moles of each of those two reactants are available. Which one will be the limiting reagent? That will be the one that runs out first. That determines how much magnesium hydroxide is produced.

zab505 · Answer

So would it be A?

anonymous · Answer

Don't guess. Look at the number of moles of each reactant available. Determine the limiting reactant. That is the one that will run out first.