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Mathematics 6 Online
OpenStudy (anonymous):

Look over my work? Medal And Fan!

OpenStudy (anonymous):

The graph provided shows the velocity f(t) of a runner during a certain time interval: Which of the following describes the intercepts on the graph? The initial acceleration of the runner was 8 m/s2, and the runner stopped after 6 seconds. The initial acceleration of the runner was 6 m/s2, and the runner stopped after 8 seconds. The initial velocity of the runner was 8 m/s, and the runner stopped after 6 seconds. The initial velocity of the runner was 6 m/s, and the runner stopped after 8 seconds.

OpenStudy (anonymous):

OpenStudy (anonymous):

I said B.

OpenStudy (anonymous):

@imer

OpenStudy (imer):

OK, you are quite close. Tell me what does "intercept" means?

OpenStudy (anonymous):

thats like an axis

OpenStudy (anonymous):

@iPwnBunnies

OpenStudy (imer):

Acceleration is the slope of the graph because y-axis is "velocity" and x-axis is "time" and we know Acceleration is change in velocity/time which the slope of the graph.

OpenStudy (anonymous):

ok

OpenStudy (imer):

y-Intercept of the graph is where the line cuts the "y-axis" where x-coordinate is always 0 and we know that it cuts at (0,6)

OpenStudy (anonymous):

Should I have not squared it? So then it is D?

OpenStudy (imer):

Well the y-axis is the velocity and not the acceleration. Therefore, the answer is "D".

OpenStudy (imer):

It's not about squaring, "m/s^2" is the unit for acceleration and "m/s" is the unit for velocity.

OpenStudy (anonymous):

Oh. Okay. Want the next question on a new post?

OpenStudy (anonymous):

Or do you want me to keep it on here?

OpenStudy (imer):

Sure, as long as you are understanding the concept.

OpenStudy (anonymous):

I do. (:

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