Question

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg(OH)2 is made?
A. The amount of MgCl2 + KOH
B. The amount of KCl
C. The amount of MgCl2
D. The amount of KOH

Answer 1

Well in this case, u hve to see which is limiting, or the number of moles which is in least, here it is MgCl2, no matter how much u increase KOH, if u dont increase Mgcl2, the amount of Mg(OH)2 remains the same

Answer 2

So would it be c?

Answer 3

yup

Answer 4

Thank you so much!