What is the percent composition of sodium hydrogen carbonate (NaHCO3)?
Na = 44.21%, H = 1.94%, C = 23.09%, O = 30.76%
Na = 30.76%, H = 1.94%, C = 23.09%, O = 44.21%
Na = 27.36%, H = 1.20%, C = 14.30%, O = 57.14%
Na = 57.14%, H = 1.20%, C = 14.30%, O = 27.36%
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OpenStudy (anonymous):
@iPwnBunnies
OpenStudy (anonymous):
is it 2nd row?
OpenStudy (anonymous):
@thushananth01
OpenStudy (anonymous):
@Somy
OpenStudy (somy):
waht is total Mr u found?
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OpenStudy (anonymous):
idk i guessed
OpenStudy (somy):
NaHCO3
Na= 23
H= 1
C= 12
O= 16*3
so total is 84 total
OpenStudy (somy):
84 = 100%
23= X
OpenStudy (somy):
this will be % of Na
do same thing for the others
OpenStudy (somy):
there is no need tho
if u find this u can understand which will be ur option
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OpenStudy (anonymous):
so wouldnt i get Na = 44.21%, H = 1.94%, C = 23.09%, O = 30.76%
OpenStudy (anonymous):
@Somy
OpenStudy (somy):
23*100/84=
OpenStudy (anonymous):
its the last row then
OpenStudy (anonymous):
@Somy
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OpenStudy (somy):
calculate it =_=
OpenStudy (anonymous):
i tried!
OpenStudy (anonymous):
:(
OpenStudy (anonymous):
idk this one
OpenStudy (somy):
u multiplied 23*100 and then divided by 84 ?
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