Question

[04.02]What coefficients must be added to balance the following reaction?

_____ Pb + _____ H3PO4 _____ H2 + _____ Pb3(PO4)2

Answer 1

@iPwnBunnies

Answer 2

3, 2, 1, 1

3, 2, 2, 1

3, 1, 3, 1

3, 2, 3, 1

Answer 3

You need the coefficients that will give you the equal amount of elements on both sides of the equation. So, like, you see that there is 3 moles of Pb on the right side, but only 1 on the left side. You'd have to put a 3 in front of the Pb on the left side.
Pretty much do this with everyone, and check again.

Answer 4

Okay and then the second part you put a two infront of it

Answer 5

Yeah, you can put a 2 in front of it. Now you need to balance the hydrogen on the right. :3

Answer 6

And that would make it a one c:

Answer 7

Wat. .-. If you put a 2 in front of H3PO4, you'll have 2*3 = 6 moles of H on the left. You need 6 moles of H on the right. ;-;

Answer 8

But the only answers I have is 1,2,and 3... .-.

Answer 9

.-. What. You have Choices A through D.
Recap. You put a 3 in the first, a 2 in the second. And a 1 in the fourth.

Answer 10

So, yeah, you need to figure out the 3rd coefficient, which is for H2.
There are 6 moles of hydrogen on the left side.
So, we need 6 moles of the hydrogen on the right side.
You'd have to put a 3 in front of the H2, because 2*3 = 6. :3

Answer 11

Oh okay c: