Question

find the sum
1/ b^2c + b/ c^2

Answer 1

\[\frac{1}{b^2c}+\frac{b}{c^2}\] common denominator will be \(b^2c^2\)

Answer 2

\[\frac{ 1 }{ b ^{2}c }+\frac{ b }{ c ^{2} }\]

Answer 3

\[\frac{c}{b^2c^2}+\frac{b^3}{b^2c^2}=\frac{c+b^3}{b^2c^2}\]

Answer 4

im confused

Answer 5

lets go slow

Answer 6

please

Answer 7

\[\frac{ 1 }{ b ^{2}c }+\frac{ b }{ c ^{2} }\] is the original question
in order to add fractions, the denominators have to be the same

Answer 8

correct

Answer 9

if you wanted to add
\[\frac{1}{3^2\times 5}+\frac{3}{5^2}\] what denominator would you have to use?

Answer 10

\[3^{2}*5^{2}\]

Answer 11

you need each factor you see to the highest power you see it so the common denominator
for \(3^25\) and \(5^2\) would be
\[3^2\times 5^2\]

Answer 12

exactly !

Answer 13

and you would have to multiply \(\frac{1}{3^2\times 5}\) by \(\frac{5}{5}\) to get
\[\frac{5}{3^2\times 5^2}\]

Answer 14

i have alot of these to do and i have no clue how to do them so do you mind helping me with them
and thats where you lost me

Answer 15

at the last step? lets make sure that is clear

Answer 16

\[\frac{1}{3^2\times 5}+\frac{3}{5^2}\] we have to write each fraction with the same denominator \(3^2\times 5^2\) right?

Answer 17

\[\frac{1}{3^2\times 5}\times \frac{5}{5}=\frac{5}{3^2\times 5^2}\\
\frac{3}{5^2}\times \frac{3^2}{3^2}=\frac{3^3}{3^2\times 5^2}\]now that the denominators are the same you can add them

Answer 18

still lost or did you get that part?

Answer 19

i will help you with the others, but lets finish this one first

Answer 20

okay thanks and why do you multiply 5 and 3

Answer 21

in my example \[\frac{1}{3^2\times 5}\] the denominator is missing a \(5\) to take is \(3^2\times 5^2\) so you have to multiply top and bottom by \(5\)

Answer 22

ooohh okay that makes sense

Answer 23

similarly
\[\frac{3}{5^2}\] the denominator is missing \(3^2\) so you have to multiply top and bottom by \(3^2\) to build up that fraction

Answer 24

now we do exactly the same thing, only with \(b\) and \(c\) instead of \(3\) and \(5\)

Answer 25

okay

Answer 26

\[\frac{ 1 }{ b ^{2}c }+\frac{ b }{ c ^{2} }\] common denominator is \(b^2\times c^2\)

Answer 27

the first one multiply top and bottom by \(c\) to get the common denominator

Answer 28

the second one multiply top and bottom by \(b^2\) to get the common denominator
lets cut to the chase

Answer 29

\[\frac{ 1 }{ b ^{2}c }+\frac{ b }{ c ^{2} }\]
\[\frac{c}{b^2c^2}+\frac{b^3}{b^2c^2}=\frac{c+b^3}{b^2c^2}\]

Answer 30

makes a little more sense

Answer 31

first fraction multiplied top and bottom by \(c\) second one top and bottom by \(b^2\)

Answer 32

wanna try another?

Answer 33

yeah

Answer 34

name it

Answer 35

one sec gotta load the page

Answer 36

something is wrong with my internet so i will have to get it to work later i will send you a message saying im on

Answer 37

k good luck