Mass of Vinegar 4.422g
Volume of NaOH used 37.89 mL
Moles of NaOH used 0.003789 C
how do you find the:
moles of HC2H3O2 neutralized, the mass of HC2H3O2, % HC2H3O2 in vinegar and the average % HC2H3O2 in vinegar?

Question

Mass of Vinegar 4.422g
Volume of NaOH used 37.89 mL
Moles of NaOH used 0.003789 C
how do you find the:
moles of HC2H3O2 neutralized, the mass of HC2H3O2, % HC2H3O2 in vinegar and the average % HC2H3O2 in vinegar?

abmon98 · Answer

Construct a Balanced equation 
CH3COOH+NaOH-->CH3COONa+H2O
Number of moles=mass/molar mass
4.422/(12*2)+(4*1)+(16*2)=0.0737
Ratio of moles are 1:1 so we use the limiting reagent which is Sodium hydroxide 
and Ethanoic acid(vinegar)is in excess. 0.0737-0.003789=0.069911 moles of CH3COOH were left unreacted. molesof CH3COOH neutralized were 0.003789

abmon98 · Answer

0.069911*60=4.19466 grams did not react.

abmon98 · Answer

(4.19466/4.422)*100=94.858%