Let X be given by its distribution function F(x) , such that f(x) = 0 if x<=0 f(x) = 1/16 x^4, if 0 < x <=2 f(x) = 1 , if x > 2. Graph the density function. Graph the distribution function F(x). I have already found E(x), Var(x), and SD(x) for this problem, but am not sure how to graph it.
seems to be a piecewise function ....
f(x) = 0 if x<=0 = 1/16 x^4, if 0 < x <=2 = 1 , if x > 2 you do realise that this is not a probability distribution right? the area under the grap is not equal to 1 is it?
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should be something akin to that
I just realized I typed the question in not quite right. Sorry about that. It is F(X)=0 if x is less than or equal to 0. F(X)= x^2 divided by 4 if 0 is less than x which is less than or equal to 2. F(X)= 1 if x is greater than 2.
Like I said the teacher wanted me to draw a graph the distribution function and the density function and find E(X), Var(X), and SD(X). I tried finding examples in our notes that fit this problem with no luck. What I am wondering is if I am supposed to plug in the E(X), Var(X), and SD(X) to graph it or just do it purely based on the information given in the question. I am not quite sure where to even begin really.
the distribution function is just the graph of the function .... for example, the distribution function for the normal distribution is the graph of e^(-x^2/2)/sqrt(2pi); which gets us the usual looking bell curve. |dw:1403550545928:dw|
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