Ask
your own question, for FREE!
Mathematics
4 Online
OpenStudy (studystagram):
For what value of k, the system of equations 2/5x+1/ky=4 and 3/5x - 6y =7 will have unique solution?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\dfrac{2}{5} x + \dfrac{1}{k} y = 4\]\[\dfrac{3}{5} x - 6y = 7\]---
Do you know the condition for a unique solution?
OpenStudy (studystagram):
Yup...I was just confused as to what to do with the 1/ky thing. Should I leave it like that or do i have to simplify or something?
OpenStudy (anonymous):
You will have to use that condition. Can you recall what it is?
OpenStudy (studystagram):
Yeah I know that...
|dw:1403553536151:dw|
OpenStudy (anonymous):
Apply the same condition here.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (studystagram):
I want to know the answer, dude
OpenStudy (anonymous):
Then find it.
OpenStudy (studystagram):
That really helps. thanks
OpenStudy (anonymous):
\[\large \dfrac{\frac{2}{5}}{\frac{3}{5}}\ne \dfrac{\frac{1}{k}}{-6}\]\[\Rightarrow \dfrac{2}{3} \ne - \dfrac{1}{6k}\]
OpenStudy (studystagram):
THIS IS EXACTLY WHERE I WAS CONFUSED. THANK YOU FOR SOLVING!!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Are you being sarcastic?
OpenStudy (studystagram):
no lol
OpenStudy (anonymous):
One thing is that \(k \ne 0\) because you can never divide by zero. And from the above equation, you will find another value that \(k\) cannot hold.
OpenStudy (studystagram):
okay. thanks again!
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
clllaaaaaire:
CLOSED
2 weeks ago
0 Replies
0 Medals