For what value of k, the system of equations 2/5x+1/ky=4 and 3/5x - 6y =7 will have unique solution?
\[\dfrac{2}{5} x + \dfrac{1}{k} y = 4\]\[\dfrac{3}{5} x - 6y = 7\]--- Do you know the condition for a unique solution?
Yup...I was just confused as to what to do with the 1/ky thing. Should I leave it like that or do i have to simplify or something?
You will have to use that condition. Can you recall what it is?
Yeah I know that... |dw:1403553536151:dw|
Apply the same condition here.
I want to know the answer, dude
Then find it.
That really helps. thanks
\[\large \dfrac{\frac{2}{5}}{\frac{3}{5}}\ne \dfrac{\frac{1}{k}}{-6}\]\[\Rightarrow \dfrac{2}{3} \ne - \dfrac{1}{6k}\]
THIS IS EXACTLY WHERE I WAS CONFUSED. THANK YOU FOR SOLVING!!
Are you being sarcastic?
no lol
One thing is that \(k \ne 0\) because you can never divide by zero. And from the above equation, you will find another value that \(k\) cannot hold.
okay. thanks again!
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