Question

how do you solve this

Answer 1

\[3\sqrt{x-3}-2=16\]

Answer 2

just add 2 to both sides then divide by 3

you get

\[3 \sqrt{x - 3} = 18\]

then

\[\sqrt{x -3} = 6\]

square both sides of the equation then add 3 to both sides to find x

Answer 3

First move the -2 to the other side, just like you would in a "regular" equation. Then you would square both sides. Gone is the radical sign. That's the point of squaring. Squaring is the opposite of taking the square root, so one "undoes" the other.

Answer 4

do i square the 3 and 6

Answer 5

squaring both sides will give you

x - 3 = 36

Answer 6

ohh

Answer 7

thanks