if cot of theta = -9/2 with theta in Quadrant 2, find the sin of theta. How do i solve this?
Oh I love these! I will help you!
First tell me what the cotangent identity is the same as (like tangent is the same as sine/cos). Give me that first.
ok i think its cos/sine?
Yes, that's right. So another way to write that is this\[\cot \theta=-\frac{ 9 }{ 2 }-->\frac{ \cos \theta }{ \sin \theta }=-\frac{ 9 }{ 2 }\]
In the second quadrant which identity is negative, cos or sin?
cosine is negative in the second quadrant
yes. Does cos represent your x value or your y value?
I wonder if there's a problem with the connection here; it seems as if you have been typing forever. and there's nothing there.
I believe it is x value
sorry my computer just froze
im back now
Yes, cos is your x value. You're doing great! So let's draw that.|dw:1403561576464:dw|
Your goal here is to find sin of that angle. In order to do that you need to find the hypotenuse, since the sin of an angle = side opposite the angle/hypotenuse, right? So can you find x?
|dw:1403561702683:dw|Just a little light humor.
What do you need to do to find x?
yes here let me do it real quick
Cool!
ok i thought i new how but i would need the angles in order to do what i was thinking
Use Pythagorean's theorem. Yes? You know it?
oh yes i know that
2^2-9^2= 85 c^2= 85 c=9.2 ? i think this is right
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