Question

What value of k solves the equation?
k^-2 = 1/64
A. 1/8
B.8
C. 32
D. 128

Answer 1

Plug in the answers and see if they work.

Answer 2

so when not written in index form the problem is

\[\frac{1}{k^2} = \frac{1}{64}\]

this should help you find k, and then find the answer

Answer 3

<3

Answer 4

keep in mind that \(\large \bf a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}\)

Answer 5

I think 1/8 or 8..

Answer 6

well k^2 = 64

so what is k

Answer 7

\(\bf \large { a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}
\\ \quad \\ \quad \\
k^{-{\color{red}{ 2}}}=\cfrac{1}{64}\implies \cfrac{1}{k^{\color{red}{ 2}}}=\cfrac{1}{64}\implies
\begin{array}{llll}
k^{\color{red}{ 2}}=64
\\ \quad \\
k=?
\end{array} }\)

Answer 8

8

Answer 9

yeap