Find the extreme values of each function on the interval!! 10 points!!? ³√(x) ; -2 ≤ x ≤ 27 answer: C) max= (27,3) and min = (0,0) This is the last problem I have and I cannot figure out how to get this answer! Can someone show me please??? Thanks in advance!!
Sorry the question says "find the ABSOLUTE extreme values of each function on the interval"
f(x) = ³√(x) f'(x) = 1/3x^(-2/3) = 1/(3x^2/3) which is positive for all values of x and is 0 at x = 0. Therefore, f(x) is an increasing function. In any interval, it will attain its maximum at the right endpoint of that interval because the function always increases as x increases.
In the interval [-2,27], f(x) will attain its maximum when x = 27 f(27) = (27)^(1/3) = 3. The max point is (27,3). When x = 0, f(x) = 0. When we take the absolute value, all the negative f(x) will become positive and the lowest or the minimum will be 0. Therefore, absolute minimum occurs at x = 0 and the point is (0,0).
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