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Simplify the difference. =]
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From factoring you should get \[\frac{(n-6)(n-4)}{(n-6)(n-7)} - \frac{9}{n-7}\] then the "n-6" terms cancel
so it would be B like i thought?
@dumbcow ?
nope because you still have to combine fractions by adding numerators \[\frac{(n-4) - 9}{n-7}\]
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I have no idea then..
just add ... n-4-9 = ?
n-13.. lol thanks
haha yw
soo C or A?
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lol well C is missing a denominator
Okay A.. I was just making sure.. lol I Cant afford anymore wrong.. lmao
:)
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