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Mathematics 7 Online
OpenStudy (anonymous):

Simplify the difference. =]

OpenStudy (anonymous):

OpenStudy (dumbcow):

From factoring you should get \[\frac{(n-6)(n-4)}{(n-6)(n-7)} - \frac{9}{n-7}\] then the "n-6" terms cancel

OpenStudy (anonymous):

so it would be B like i thought?

OpenStudy (anonymous):

@dumbcow ?

OpenStudy (dumbcow):

nope because you still have to combine fractions by adding numerators \[\frac{(n-4) - 9}{n-7}\]

OpenStudy (anonymous):

I have no idea then..

OpenStudy (dumbcow):

just add ... n-4-9 = ?

OpenStudy (anonymous):

n-13.. lol thanks

OpenStudy (dumbcow):

haha yw

OpenStudy (anonymous):

soo C or A?

OpenStudy (dumbcow):

lol well C is missing a denominator

OpenStudy (anonymous):

Okay A.. I was just making sure.. lol I Cant afford anymore wrong.. lmao

OpenStudy (dumbcow):

:)

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