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Simplify the sum. <3
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@dumbcow
Are you able to factor a trinomial? All the four trinomials are factoable!
*factorable
i have noo idea,,,
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I know its not C.. is it D?
@mathmale
@phi
@zzr0ck3r
\[\frac{d^2+d-30}{d^2+3d-40}\]\[=\frac{(d+6)(d-5)}{(d+8)(d-5)}\] is a start then cancel get \[\frac{d+6}{d+8}\]for the first term repeat for the second fraction
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I know it is A or D
It is A! righT?
What did you get for the reduced version of the second term?
\[\frac{(d^2+14d+48)}{(d^2-2d-48)}\] \[=\frac{(d+6)(d+8)}{(d+6)(d-8)}\] which can be simplified to \[\frac{d+8}{d-8} \ \ if\ d\ne 6\]
Now you can do the sum: \[\frac{d+6}{d-8}+\frac{d+8}{d-8}\] to get the final answer.
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