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Mathematics 9 Online
OpenStudy (anonymous):

Simplify the sum. <3

OpenStudy (anonymous):

OpenStudy (anonymous):

@dumbcow

OpenStudy (mathmate):

Are you able to factor a trinomial? All the four trinomials are factoable!

OpenStudy (mathmate):

*factorable

OpenStudy (anonymous):

i have noo idea,,,

OpenStudy (anonymous):

I know its not C.. is it D?

OpenStudy (anonymous):

@mathmale

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

@zzr0ck3r

OpenStudy (anonymous):

\[\frac{d^2+d-30}{d^2+3d-40}\]\[=\frac{(d+6)(d-5)}{(d+8)(d-5)}\] is a start then cancel get \[\frac{d+6}{d+8}\]for the first term repeat for the second fraction

OpenStudy (anonymous):

I know it is A or D

OpenStudy (anonymous):

It is A! righT?

OpenStudy (mathmate):

What did you get for the reduced version of the second term?

OpenStudy (mathmate):

\[\frac{(d^2+14d+48)}{(d^2-2d-48)}\] \[=\frac{(d+6)(d+8)}{(d+6)(d-8)}\] which can be simplified to \[\frac{d+8}{d-8} \ \ if\ d\ne 6\]

OpenStudy (mathmate):

Now you can do the sum: \[\frac{d+6}{d-8}+\frac{d+8}{d-8}\] to get the final answer.

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