Question

lim e^-x +5/4^1/x as x approaches positive infinity

Answer 1

\(\lim_{x\rightarrow \infty}e^{-x}+(\frac{5}{4})^{\frac{1}{x}}\)?

Answer 2

@vicky38 ??

Answer 3

no its plus 5 divide by 4 to the 1over x power

Answer 4

\(\frac{e^{-x}+5}{4^{\frac{1}{x}}}\)

Answer 5

lim e-x + 5 (l) lim 4 – x
x® ∞ 41/x
yes

Answer 6

well \(e^{-x}=\frac{1}{e^x}\rightarrow \frac{1}{\infty}=0 \) as \(x\rightarrow \infty\)
and \(4^{\frac{1}{x}}\rightarrow 4^{\frac{1}{\infty}}\rightarrow 4^0=1 \) as \(x\rightarrow \infty\)
so we have \(\frac{0+5}{1}=5\)

Answer 7

ignore the first mail
the attached doc i am doing the letter k on it

Answer 8

how would letter O work out

Answer 9

\(\frac{2}{\infty} \rightarrow0\) so \(8\)

Answer 10

thanks for the other problem
had the same idea just did not know how to finish the thought

Answer 11

what about letter L