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Solve for x: .95=[(e^x)-1]/x Step by step would be appreciated
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\(\bf 0.95=\cfrac{e^x-1}{x}\qquad or \qquad 0.95=\cfrac{e^{x-1}}{x}\quad ?\)
lets hope the first one, else im not sure anyone here can do it.
heh
yeah sorry it's the first one
\[0.95 = \frac {e^x - 1} {x}\] \[\ 0.95x = e^x -1\] \[\ 0.95x + 1 = e^x \]
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hmmm
"Solve for x:" =)
well yeah, you would just take the log of both sides from there
well.. ahemm wouldn't that land us at ln(0.95x+1) = x ?
\[\ \ln(.95x + 1) = \ln e^x\] \[\ \ln (.95x + 1) = x \] hehe
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that's where i got stuck
hehe
hmm
wolfram gave a weird answer
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