Question

Estimate the volume of juice in ounces that the cylinder will hold. Round to the nearest tenth of an ounce. (Hint: 1 in3 ≈ 0.55 oz.)

Answer 1

We'll need more information than that to solve the problem. However, the volume of a cylinder can be found using V = π(r^2)h where r is the radius of the cylinder and h is it's height. Then convert inches to ounces and you have your answer!

Answer 2

https://courseplayer.avalearning.com/NeutralLMS/coursefiles/Questions/847684/straw2.png


24.0 oz
19.4 0z
20.7 oz
23.2 oz

Answer 3

is the height will be 6 rite?

Answer 4

the answer would be 24.0 oz
rite?

Answer 5

How did you get a height of 6?

Answer 6

im trying to find the straws height since its diagonal to the
main height . the straws height is 7 rite?

Answer 7

I would say the total length of the straw is closer to 5. But that means the length inside the can is 4...which can't be the case since the straw is the hypotenuse of a right triangle with 4 as the base, and the base can't be the same as the hypotenuse.

Also the 1 inch outside the can is definitely not a quarter of the length of the base, meaning the drawing isn't to scale, and so estimating the length is going to be problematic. Unless there's something I'm missing, I don't see how you can get 6 for the length of the straw...

Answer 8

oh okay
i thought it was
so it wouldnt be 24.0 oz or it has to be
smaller?

Answer 9

To be honest I'm not sure based on the drawing you gave. You need to find the height of the can using the Pythagorean Theorem, and you do that by estimating the length of the straw inside the can. But the two lengths given in the picture don't match up, so estimating the length of the straw isn't really useful, and the value you get if you do isn't reasonable. If you take the 1 inch length in the picture and lay it back to back 4 times to make 4 inches, it's longer than the "4 inch" base of the can. The picture doesn't make sense...

Not sure what to say...hopefully someone else will have a look at this and see something I haven't...

Answer 10

thanks for your help.

Answer 11

No problem too bad I couldn't give you a definitive answer lol

Answer 12

well its okay
next time