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Algebra 21 Online
OpenStudy (anonymous):

The function f(x) = x2. The graph of g(x) is f(x) translated to the left 6 units and down 5 units. What is the function rule for g(x)? A. g(x) = (x + 6)2 - 5 B. g(x) = (x - 5)2 + 6 C. g(x) = (x - 6)2 + 5 D. g(x) = (x + 5)2 - 6

OpenStudy (anonymous):

A

OpenStudy (anonymous):

So a parabola has the generic formula: \[y=(x-h)^{2} + k\] where (h,k) is the bottom/top of the parabola

OpenStudy (anonymous):

So what is the bottom/top of the parabola of \[y=x^{2}\]

OpenStudy (anonymous):

How do you know it's a?

OpenStudy (anonymous):

Take a look at what I posted above. I'll walk you through it!

OpenStudy (anonymous):

Okay okay :) Okay so...what next?

OpenStudy (anonymous):

The easiest way to figure out the new graph is to figure out how the bottom/top of the graph moved. So we have \[y = x^{2} \] what would be the coordinate of the bottom/top?

OpenStudy (anonymous):

y= -x^2?

OpenStudy (anonymous):

I'm just looking for an (x,y) coordinate. So the generic formula for a parabola is \[y = (x-h)^{2} + k\] where (h,k) is the coordinate of the bottom/top of the parabola. So now we have \[y = x^{2}\] which is the same as \[y=(x-0)^{2} + 0\] so what is the (x,y) coordinate of the bottom/top?

OpenStudy (anonymous):

im so confused /.\

OpenStudy (anonymous):

Okay, which part is confusing?

OpenStudy (anonymous):

( h,k) ?

OpenStudy (anonymous):

So (h,k) is called the vertex of the parabola, which is like the bottom of the dip in a graph. |dw:1403570694596:dw| The circled part in the graph is the vertex.

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