Question

Find the line that passes through(1,2) and the parallel to the line with x-intercept -3 and y-intercept of 10

Answer 1

a line with x intercept (-3,0) and y intercept (0,10) has slope \(?\)

Answer 2

dont wait for dan to show off, ANSWER ME.....

Answer 3

jk

Answer 4

lool

Answer 5

Do it!! find the slope be a man!

Answer 6

would i use m=y-y1/x-x1

Answer 7

10-2/-3-1=-2

Answer 8

ok yes we would use \(m=\frac{y_0-y_1}{x_0-x_1}\) but our given points are \((-3,0)\) and \((0,10)\)

Answer 9

so our slope is ?

Answer 10

For two lines to be parallel, both lines MUST have the same slope.
To find the slope of the given equation, modify it into the "slope-intercept" form of:
y = mx + b
where
m is the slope
b is the y-intercept at (0,b)
.
5 = -10x - 10y
10y + 5 = -10x
10y = -10x - 5
y = -x - 5
.

From the above we know the slope is a -1.
Now to find the 'y-intercept' of the new line, use that fact AND the given point of (-2, 1) to plug it back into:
y = mx + b
1 = (-1)(-2) + b
1 = 2 + b
-1= b
.
Recapping, we have:
m = -1
b = -1
therefore the equation is:
y = mx + b
y = -x -1 (this is the equation)

Answer 11

yikes our line will have slope \(m=\frac{10-0}{0-(-3)}=\frac{10}{3}\)

Answer 12

do you see how I got that?

Answer 13

that's what i got and then i would plug it in y-y1=m(x-x1)